To determine which element has atoms with valence electrons in a higher energy level than those of calcium (Ca), we must first note that calcium (Ca) is in Group 2 and has an atomic number of 20. Its electron configuration is \(1s^2 2s^2 2p^6 3s^2\), meaning its valence electrons are in the third energy level (n=3).
Now let's look at the other options:
- Oxygen (O): Atomic number 8, electron configuration \(1s^2 2s^2 2p^4\). Valence electrons are in the second energy level (n=2).
- Bromine (Br): Atomic number 35, electron configuration \(1s^2 2s^2 2p^6 3s^2 3p^5\). Valence electrons are in the fourth energy level (n=4).
- Lithium (Li): Atomic number 3, electron configuration \(1s^2 2s^1\). Valence electrons are in the second energy level (n=2).
- Cesium (Cs): Atomic number 55, electron configuration \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 4p^6 5s^1\). Valence electrons are in the sixth energy level (n=6).
Given this information, both bromine (Br) and cesium (Cs) have valence electrons in a higher energy level than calcium. However, since the question is likely seeking a single answer, cesium (Cs) is the one with valence electrons in the highest energy level.
Therefore, the answer is:
cesium (Cs).