Asked by ggget PHYSICal
An electron is relased into a uniform electric field of magnitude 8.35 N/C. How many times larger is this electrons acceleration than the acceleration due to gravity on the surface of Earth?
Is it just F= qE = ma (for the electron, and using E for electric field), and then take the a as a ratio of g? It seemed too simple, I'm afraid I'm missing a variable.
Is it just F= qE = ma (for the electron, and using E for electric field), and then take the a as a ratio of g? It seemed too simple, I'm afraid I'm missing a variable.
Answers
Answered by
bobpursley
set qE=mg*k
solve for k
solve for k
Answered by
Sammy
Hi, I tried this question...should we use g as -9.8m/s^2?
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