To evaluate the implications of \( cd \) and \( ad + bc \cdot bd \) being rational numbers for \( ab \):
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Since \( cd \) is rational, it suggests that both \( c \) and \( d \) could be rational or at least their product results in a rational number.
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For \( ad + bc \cdot bd \) to also be rational, we examine the components:
- If \( a \) and \( b \) are rational, then \( ab \) would be rational.
- If \( c \) and \( d \) are rational, \( cd \) is rational, potentially allowing various combinations of rational and irrational numbers.
However, it's important to focus on how rational results from \( ad + bc \cdot bd \) can affect \( ab \).
- Given that \( cd \) is rational, if \( a \) is rational and \( b \) is rational then \( ab \) is rational.
- Even if \( a \) or \( b \) is irrational, the terms combined in \( ad + bc \cdot bd \) may produce a result that seems rational based on their interactions.
The specific question is not amenable to straightforward deduction without more context about the individual values. Still, we can conclude that \( ab \) must be rational if both conditions ensure that coefficients multiply rationally.
Therefore, given the options presented:
Option 1: ab is rational is correct.
So, the answer is 1.