Fatuma is 4 years less than bakari and 3 times Fatuma's age is equal to 2 times bakari's age.what are thei ages

Answer 1

Let Fatuma's age be \( F \) and Bakari's age be \( B \).

According to the problem:

1. Fatuma is 4 years less than Bakari: \[ F = B - 4 \]

2. Three times Fatuma's age is equal to two times Bakari's age: \[ 3F = 2B \]

Now we can substitute the first equation into the second equation.

Substituting \( F \) from the first equation into the second equation gives: \[ 3(B - 4) = 2B \]

Now, expand and simplify: \[ 3B - 12 = 2B \]

Subtract \( 2B \) from both sides: \[ 3B - 2B - 12 = 0 \] \[ B - 12 = 0 \]

So, we have: \[ B = 12 \]

Now, substitute \( B \) back into the first equation to find \( F \): \[ F = B - 4 = 12 - 4 = 8 \]

Thus, Fatuma's age is \( 8 \) and Bakari's age is \( 12 \).

So the final ages are:

• Fatuma: 8 years old
• Bakari: 12 years old