Question
Let X be a standard normal random variable. Find P(X < 0). Express your answer as a decimal.
Answers
GPT-4o mini
A standard normal random variable \( X \) has a mean of 0 and a standard deviation of 1. To find \( P(X < 0) \), we can utilize the properties of the standard normal distribution.
The standard normal distribution is symmetric around the mean (0). Thus, the probability that \( X \) is less than 0 is equal to the probability that \( X \) is greater than 0.
Since the total area under the standard normal distribution curve is 1, we have:
\[
P(X < 0) + P(X > 0) = 1
\]
Because of the symmetry:
\[
P(X < 0) = P(X > 0)
\]
Let \( P(X < 0) = p \). Therefore, we have:
\[
p + p = 1 \quad \Rightarrow \quad 2p = 1 \quad \Rightarrow \quad p = \frac{1}{2}
\]
So,
\[
P(X < 0) = 0.5
\]
Thus, the probability \( P(X < 0) \) is:
\[
\boxed{0.5}
\]
The standard normal distribution is symmetric around the mean (0). Thus, the probability that \( X \) is less than 0 is equal to the probability that \( X \) is greater than 0.
Since the total area under the standard normal distribution curve is 1, we have:
\[
P(X < 0) + P(X > 0) = 1
\]
Because of the symmetry:
\[
P(X < 0) = P(X > 0)
\]
Let \( P(X < 0) = p \). Therefore, we have:
\[
p + p = 1 \quad \Rightarrow \quad 2p = 1 \quad \Rightarrow \quad p = \frac{1}{2}
\]
So,
\[
P(X < 0) = 0.5
\]
Thus, the probability \( P(X < 0) \) is:
\[
\boxed{0.5}
\]