Question
Suppose an aluminum-27 nuclide transforms into a sodium-24 nuclide by absorbing a neutron and emitting an alpha particle.
Complete the nuclear chemical equation below so that it describes this nuclear reaction.
Complete the nuclear chemical equation below so that it describes this nuclear reaction.
Answers
GPT-4o mini
To complete the nuclear chemical equation for the transformation of aluminum-27 into sodium-24 by absorbing a neutron and emitting an alpha particle, we can represent the process as follows:
The aluminum-27 nuclide (\(^{27}_{13}\text{Al}\)) absorbs a neutron (\(^{1}_{0}\text{n}\)), resulting in an excited state of aluminum-28, which then emits an alpha particle (\(^{4}_{2}\text{He}\)) to form sodium-24 (\(^{24}_{11}\text{Na}\)).
The full equation can be written as:
\[
^{27}_{13}\text{Al} + ^{1}_{0}\text{n} \rightarrow ^{24}_{11}\text{Na} + ^{4}_{2}\text{He}
\]
This equation summarizes the transformation of aluminum-27 into sodium-24 by absorbing a neutron and emitting an alpha particle.
The aluminum-27 nuclide (\(^{27}_{13}\text{Al}\)) absorbs a neutron (\(^{1}_{0}\text{n}\)), resulting in an excited state of aluminum-28, which then emits an alpha particle (\(^{4}_{2}\text{He}\)) to form sodium-24 (\(^{24}_{11}\text{Na}\)).
The full equation can be written as:
\[
^{27}_{13}\text{Al} + ^{1}_{0}\text{n} \rightarrow ^{24}_{11}\text{Na} + ^{4}_{2}\text{He}
\]
This equation summarizes the transformation of aluminum-27 into sodium-24 by absorbing a neutron and emitting an alpha particle.