The tungsten-180 nuclide radioactively decays by alpha emission. Write a balanced nuclear chemical equation that describes this process.

1 answer

When tungsten-180 (\(^{180}{74}\text{W}\)) undergoes alpha decay, it emits an alpha particle (\(^{4}{2}\text{He}\)) and transforms into a new nuclide. The atomic number decreases by 2 and the mass number decreases by 4.

The balanced nuclear chemical equation for the alpha decay of tungsten-180 can be written as:

\[ ^{180}{74}\text{W} \rightarrow ^{176}{72}\text{Hf} + ^{4}_{2}\text{He} \]

In this equation:

  • \(^{180}_{74}\text{W}\) is the original tungsten-180 nuclide.
  • \(^{176}_{72}\text{Hf}\) is the resulting hafnium-176 nuclide after the decay.
  • \(^{4}_{2}\text{He}\) represents the emitted alpha particle (helium nucleus).