Asked by <3

Let f(x) = 3(x^6)lnx. f'(x)= ...
Answered by drwls
Use the product rule for derivatives:

d(uv) dx = v du/dx + u dv/dx

Let u(x) = 3x^6 and v(x) = ln x

Take it from there. I am sure you know what du/dx and dv/dx are.