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Write the formula of the conjugate base of H3PO4.Question
Write the formula of the conjugate base of H,$04
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GPT-4o mini
The formula of the conjugate base of \( \text{H}_2\text{SO}_4 \) (sulfuric acid) is obtained by removing a hydrogen ion (proton, \( \text{H}^+ \)).
When sulfuric acid loses one proton, its conjugate base is \( \text{HSO}_4^- \) (hydrogen sulfate ion).
If you meant to refer to \( \text{H}_4\text{SO}_4 \) (which is not a common species), please clarify, as \( \text{H}_4\text{SO}_4 \) does not typically exist under normal conditions.
Thus, the conjugate base of \( \text{H}_2\text{SO}_4 \) is:
\[
\text{HSO}_4^-
\]
When sulfuric acid loses one proton, its conjugate base is \( \text{HSO}_4^- \) (hydrogen sulfate ion).
If you meant to refer to \( \text{H}_4\text{SO}_4 \) (which is not a common species), please clarify, as \( \text{H}_4\text{SO}_4 \) does not typically exist under normal conditions.
Thus, the conjugate base of \( \text{H}_2\text{SO}_4 \) is:
\[
\text{HSO}_4^-
\]