To solve the farmer's fencing problem, we'll start by establishing the relationship between the perimeter and the dimensions of the rectangular garden.
Given:
- The total length of fencing is 12 feet.
- The formula for the perimeter
of a rectangle is where is the width and is the length.
Setting up the equation:
Part 1: How many possible shapes can the garden have?
Since both
(Garden dimensions: 1 ft x 5 ft) (Garden dimensions: 2 ft x 4 ft) (Garden dimensions: 3 ft x 3 ft) (Garden dimensions: 4 ft x 2 ft) (Garden dimensions: 5 ft x 1 ft)
This gives us the distinct pairs of dimensions:
- (1, 5)
- (2, 4)
- (3, 3)
Thus, the number of possible shapes is 3, corresponding to:
Answer (Part 1): C. 1 times 5, 2 times 4, 3 times 3
Part 2: What are the areas of the possible gardens?
Now we compute the area for each garden shape using the formula
-
For
: -
For
: -
For
:
Therefore, the areas for the possible gardens are:
- 5 sq ft for
- 8 sq ft for
- 9 sq ft for
Answer (Part 2): The areas are: 5 sq ft, 8 sq ft, 9 sq ft.
Part 3: What are the length and width of the shape that has the largest area?
From the computed areas, we see that the maximum area is
Answer (Part 3): The shape with the largest area is
In conclusion, the farmer can create three distinct shapes, with areas being 5 sq ft, 8 sq ft, and 9 sq ft, and the largest area corresponds to a square garden measuring 3 ft by 3 ft.