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An underwater diving area for snorkelers and scuba divers located in a city is designated by buoys and ropes, making the divin...Question
An underwater diving area for snorkelers and scuba divers located in a city is designated by buoys and ropes, making the diving section into the shape of a trapezoid on the surface of the water. The trapezoid has a height of 265 meters. The bases are 310 meters and 270 meters. Find the area of the diving section.
The area of the diving section is
The area of the diving section is
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Answered by
GPT-4o mini
To find the area of a trapezoid, you can use the formula:
\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height.
Given:
- \( b_1 = 310 \) meters (the length of the longer base)
- \( b_2 = 270 \) meters (the length of the shorter base)
- \( h = 265 \) meters (the height)
Now, substitute the values into the formula:
\[
\text{Area} = \frac{1}{2} \times (310 + 270) \times 265
\]
First, calculate \( b_1 + b_2 \):
\[
310 + 270 = 580
\]
Now substitute that back into the formula:
\[
\text{Area} = \frac{1}{2} \times 580 \times 265
\]
Now, calculate \( \frac{1}{2} \times 580 \):
\[
\frac{1}{2} \times 580 = 290
\]
Finally, calculate the area:
\[
\text{Area} = 290 \times 265 = 76,850 \text{ square meters}
\]
Thus, the area of the diving section is
\[
\boxed{76,850} \text{ square meters}.
\]
\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]
where \( b_1 \) and \( b_2 \) are the lengths of the two bases, and \( h \) is the height.
Given:
- \( b_1 = 310 \) meters (the length of the longer base)
- \( b_2 = 270 \) meters (the length of the shorter base)
- \( h = 265 \) meters (the height)
Now, substitute the values into the formula:
\[
\text{Area} = \frac{1}{2} \times (310 + 270) \times 265
\]
First, calculate \( b_1 + b_2 \):
\[
310 + 270 = 580
\]
Now substitute that back into the formula:
\[
\text{Area} = \frac{1}{2} \times 580 \times 265
\]
Now, calculate \( \frac{1}{2} \times 580 \):
\[
\frac{1}{2} \times 580 = 290
\]
Finally, calculate the area:
\[
\text{Area} = 290 \times 265 = 76,850 \text{ square meters}
\]
Thus, the area of the diving section is
\[
\boxed{76,850} \text{ square meters}.
\]
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