A line has the equation 2x-3y-18=0

Express the equation of the line in the form y=mx+c

1 answer

To express the equation of the line in the form y=mx+c, we need to isolate y in the given equation.

2x - 3y - 18 = 0
Subtract 2x from both sides:
-3y - 18 = -2x
Add 18 to both sides:
-3y = -2x + 18
Divide by -3:
y = (2/3)x - 6

Therefore, the equation of the line in the form y=mx+c is y = (2/3)x - 6.