the radio of chattboxes to blabbermouths at the semi annual gal a was 3 to 4. if there were 165 chatterboxes, how many blabbermouths were there?

Answer 1

Let's denote the number of chatterboxes as x and the number of blabbermouths as y.

Given that the ratio of chatterboxes to blabbermouths is 3:4, we can write the equation:

x/y = 3/4

Since there were a total of 165 chatterboxes, we can write another equation:

x + y = 165

Now we can use these two equations to solve for the number of blabbermouths:

x = (3/4)y
y = 165 - x

Substitute the second equation into the first equation:

(3/4)y = 165 - y

Multiplying both sides by 4:

3y = 660 - 4y
7y = 660
y = 660/7
y = 94.29

We can't have a fraction of a person, so we round down to the nearest whole number:

y ≈ 94

Therefore, there were approximately 94 blabbermouths at the semi-annual gala.