A 360mL sample of hydrogen gas is collected when the pressure is 800 mm HG at room temperature. What is the volume that the gas will occupy when the pressure is 720 mm HG and the temperature is 0 degrees?

Answer 1

To solve this problem, we can use the combined gas law formula:

(P1)(V1)/(T1) = (P2)(V2)/(T2)

Where:
P1 = initial pressure = 800 mm Hg
V1 = initial volume = 360 mL
T1 = initial temperature = room temperature (we need to convert this to Kelvin)
P2 = final pressure = 720 mm Hg
V2 = final volume (what we need to solve for)
T2 = final temperature = 0 degrees Celsius (we need to convert this to Kelvin)

First, let's convert the temperatures to Kelvin:
Room temperature = 20 degrees Celsius = 293 K
Final temperature = 0 degrees Celsius = 273 K

Now, plug the values into the formula:

(800 mm Hg)(360 mL)/(293 K) = (720 mm Hg)(V2)/(273 K)

Solve for V2:
V2 = (800 mm Hg * 360 mL * 273 K) / (720 mm Hg * 293 K)
V2 = 77040 / 210960
V2 = 0.365 mL

Therefore, the volume that the gas will occupy when the pressure is 720 mm Hg and the temperature is 0 degrees Celsius is approximately 0.365 mL.