A gas in a rigid container has a pressure of 2.5atm at 25 degrees. It is placed in a freezer at standard temperature. What will the new pressure be?

Answer 1

To find the new pressure, we can use the ideal gas law formula:

P1V1/T1 = P2V2/T2

Where:
P1 = initial pressure = 2.5 atm
V1 = initial volume (constant)
T1 = initial temperature = 25°C = 298 K
P2 = final pressure = ?
V2 = final volume (constant)
T2 = final temperature = standard temperature = 0°C = 273 K

Since the volume is constant, we can simplify the formula to:

P1/T1 = P2/T2

Now we can plug in the values and solve for P2:

(2.5 atm) / (298 K) = P2 / (273 K)

P2 = (2.5 atm) * (273 K) / (298 K)
P2 = 2.285 atm

Therefore, the new pressure of the gas after being placed in the freezer at standard temperature is 2.285 atm.