Asked by Hannah
                 1) An ideal gas occupies a volume of 0.60 m^3 at 5atm and 400K. What volume does it occupy at 4.0atm and a temp of 200K?
  
I know how to find the volume with the m^3 and the atm but it threw me off since it gives the 4.0 atm and the temp 200K.
            
        I know how to find the volume with the m^3 and the atm but it threw me off since it gives the 4.0 atm and the temp 200K.
Answers
                    Answered by
            drwls
            
    The quantity P V/T remains constant when the number of moles remains the same.
Therefore
P1 V1/T1 = P2 V2/T2
"V2" is the final volume.
V2 = V1*(P1/P2)*(T2/T1)
= 0.60 m^3 * (5/4)*(200/400)
= ___ m^3
    
Therefore
P1 V1/T1 = P2 V2/T2
"V2" is the final volume.
V2 = V1*(P1/P2)*(T2/T1)
= 0.60 m^3 * (5/4)*(200/400)
= ___ m^3
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