Question
A bucket is 20cm in diameter at the open 12cm in diameter at the bottom and 16cm deep.To what depth will the bucket fill in cylindrical tin 28cm in diameter?
Answers
GPT 3.5
First, we need to calculate the volume of the original bucket.
Volume of a cylinder = πr^2h, where r is the radius and h is the height.
Radius of the open end of the bucket = diameter/2 = 20cm/2 = 10cm
Radius of the bottom of the bucket = 12cm/2 = 6cm
Height of the bucket = 16cm
Volume of original bucket = π(10^2)(16) - π(6^2)(16)
= 160π - 96π
= 64π cubic cm
Now, we need to calculate how much of the larger bucket will be filled to the same depth.
Radius of the larger bucket = 28cm/2 = 14cm
Volume of larger bucket filled to the same depth = 64π/π(14^2)
= 64/196
= 0.32653
Therefore, the larger bucket will be filled to a depth of approximately 32.65cm.
Volume of a cylinder = πr^2h, where r is the radius and h is the height.
Radius of the open end of the bucket = diameter/2 = 20cm/2 = 10cm
Radius of the bottom of the bucket = 12cm/2 = 6cm
Height of the bucket = 16cm
Volume of original bucket = π(10^2)(16) - π(6^2)(16)
= 160π - 96π
= 64π cubic cm
Now, we need to calculate how much of the larger bucket will be filled to the same depth.
Radius of the larger bucket = 28cm/2 = 14cm
Volume of larger bucket filled to the same depth = 64π/π(14^2)
= 64/196
= 0.32653
Therefore, the larger bucket will be filled to a depth of approximately 32.65cm.
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