Question

Suppose a camper took 2 h to ride around a resevoir at 10 mi/h at the beginning of the summer. By the end of the summer, s h. What is her rate at the end of the summer?

Answer 1

Let x be the total distance around the reservoir.

At the beginning of the summer:
Time = 2 hours
Rate = 10 mi/h

Distance = Rate * Time
Distance = 10 * 2
Distance = 20 miles

At the end of the summer:
Time = s hours
Rate = x/s mi/h

The total distance around the reservoir is the same, so:
20 = (x/s) * s
20 = x

Now we can substitute this value of x back into the equation for the rate at the end of the summer:
Rate = x/s
Rate = 20/s

Therefore, the camper's rate at the end of the summer is 20/s miles per hour.