A train moving at a constant speed of 68.0 km/h moves east for 36.0 min, then in a direction 48.0° east of due north for 30.0 min, and then west for 45.0 min. What is the average velocity of the train during this run?

Answer 1

Find its end position.

End position=68*36/60 E + 68*1/2*(Cos48 N + sin48E)- 68*45/60 E

Average veocity= endposition-start position/ timetotal and the start position is zero.