Asked by Anonymous
A canoe has a velocity of 0.490 southeast relative to the earth. The canoe is on a river that is flowing at 0.520 east relative to the earth creating a 45 degree angel between the two velocities.Find the magnitude of the velocity of the canoe relative to the river.
Answers
Answered by
drwls
Perform the vector operation:
Vce = Vwe + Vcw where
Vce = velocity of cane with respaect to earth
Vwe = velocity of water (river) with respect to earth
Vcw = velocity of canoe with respect to water. (You want to know its magnitude)
You have not provided units for your velocity numbers, so that is as far as I can go with this one.
Vce is at a 45 degree angle to Vwe.
There are two unknowns: the magnitude of Vcw and its direction. The vector equation will provide the two equations needed (one for east-west and one for north-south components)
Vce = Vwe + Vcw where
Vce = velocity of cane with respaect to earth
Vwe = velocity of water (river) with respect to earth
Vcw = velocity of canoe with respect to water. (You want to know its magnitude)
You have not provided units for your velocity numbers, so that is as far as I can go with this one.
Vce is at a 45 degree angle to Vwe.
There are two unknowns: the magnitude of Vcw and its direction. The vector equation will provide the two equations needed (one for east-west and one for north-south components)
Answered by
Anonymous
565
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