A train left a station at noon traveling at 40mph. A second train left at 3 PM travelling at 60mph. at what time will the second train catch up with the first?

Answer 1

Let x be the number of hours it takes for the second train to catch up with the first train.

Distance = speed * time

For the first train:
Distance = 40 * x

For the second train:
Distance = 60 * (x - 3)

Since both trains will travel the same distance when they meet:

40x = 60(x - 3)

40x = 60x - 180

20x = 180

x = 9

Therefore, the second train will catch up with the first train 9 hours after it left the station, which will be at 12 PM + 9 hours = 9 PM.