To find the acceleration of the car, we need to calculate the net force acting on the car. The forces acting on the car are:
1. The force of the tow truck pulling the car forward: 7,000 N [E]
2. The force of kinetic friction resisting the motion of the car: FK = μk * N, where μk is the coefficient of kinetic friction and N is the normal force acting on the car. The normal force is equal to the weight of the car since it is on a flat surface, so N = mg = 1,200 kg * 9.8 m/s^2 = 11,760 N. Therefore, FK = 0.80 * 11,760 N = 9,408 N [W]
Since the force of kinetic friction is in the opposite direction of the pulling force, we need to subtract it from the force of the tow truck:
Net force = 7,000 N [E] - 9,408 N [W] = -2,408 N
Now we can use Newton's second law to find the acceleration of the car:
Fnet = ma
-2,408 N = 1,200 kg * a
a = -2,408 N / 1,200 kg
a ≈ -2 m/s^2
Therefore, the acceleration of the car, when the tires slide across the road and the tow truck pulls it forward, is approximately -2 m/s^2. The negative sign indicates that the car is decelerating.
In an action movie, a 1,200 kg car is pulled forward by a tow truck with a force of 7,000 N [E]. The hero in the movie hits the brakes in the car to try to get free from the tow truck. The coefficient of kinetic friction between the car’s tires and the road is 0.80.
Find the acceleration of the car when the tires slide across the road and the tow truck pulls it forward.
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