FBD of the rock:
- Force of tractor pulling to the right: 1200 N
- Force of friction acting to the left: 750 N
- Weight of the rock acting downwards: mg = 150 kg * 9.8 m/s^2 = 1470 N
Net force in the horizontal direction:
Fnet = 1200 N - 750 N
Fnet = 450 N to the right
Therefore, the magnitude of the net force acting on the rock is 450 N to the right.
A tractor pulls a 150 kg rock to the right with a force of 1200 N against a force of friction of 750 N [left].
• Draw a FBD of the rock, and determine the magnitude and direction of the net force acting on the rock
1 answer
1 answer