A tractor pulls a 150 kg rock to the right with a force of 1200 N against a force of friction of 750 N [left].

• Draw a FBD of the rock, and determine the magnitude and direction of the net force acting on the rock.

1 answer

In the FBD of the rock:
- The force of gravity (weight) acts downward
- The force of the tractor pulling the rock to the right (1200 N) acts to the right
- The force of friction acting in the opposite direction of motion (750 N) acts to the left

The net force can be calculated as follows:
Net force = Force pulling to the right - Force of friction to the left
Net force = 1200 N - 750 N
Net force = 450 N to the right

Therefore, the magnitude of the net force acting on the rock is 450 N to the right.