The values of x and y are x = 17, y = 15.
Given that m3 = 4y, and m4 = 112. Since m4 = 112, m3 = m4/28 = 112/28 = 4, which means m3 = 4. Thus, 4y = 4, so y = 4/4 = 1.
Given that m2 = 7x + 7, and m4 = 112. Since m4 = 112, m2 = (112 - 7)/7 = 105/7 = 15.
Therefore, x = 15 and y = 1, which is x = 15, y = 17.
21.
If m 2 = 7x + 7, m 3 = 4y, and m 4 = 112, find the values of x and y.
x = 15, y = 17
x = 112, y = 68
x = 68, y = 112
x = 17, y = 15
1 answer