A metre rule is balance by masses of 24g and 16g suspended from its end find the position of its pivot

Answer 1

Let x be the position of the pivot from the end where the 24g mass is suspended.

The sum of anticlockwise moments = sum of clockwise moments
24g * (1 - x) = 16g * x
24 - 24x = 16x
40x = 24
x = 24/40
x = 0.6

Therefore, the pivot is at a distance of 0.6m from the end where the 24g mass is suspended.