69. Let x be the common ratio. Rishabh bought 4x metres of shirt material for every 3x metres of skirt material.
Cost of skirt material = 80 * 3x = 240x
Cost of shirt material = 40 * 4x = 160x
Total cost = 240x + 160x = 400x
Selling price of skirt material = 1.12 * 240x = 268.8x
Therefore, the sale price of skirt material is option (B) 268.8x.
70. Selling price of shirt material = 1.10 * 160x = 176x
Therefore, the sale price of shirt material is option (D) 176x.
71. Total sale = Selling price of skirt material + Selling price of shirt material
Total sale = 268.8x + 176x = 444.8x
Therefore, the total sale is option (C) 444.8x.
72. If the total sale is Rs 44480, then x = Total sale / 444.8
x = 44480 / 444.8
x = 100
Therefore, x = 100 and the answer is option (A) 100.
73. Total sale = Selling price of skirt material + Selling price of shirt material
44480 = 268.8x + 176x
44480 = 444.8x
x = 44480 / 444.8
x = 100
Rishabh bought 4x metres of shirt material, so
Shirt material bought = 4 * 100 = 400 metres
Therefore, Rishabh bought 400 metres of shirt material when the total sale is Rs 44480. The answer is option (B) 400 metres.
Rish kind of doth mater to purchase cloth materials for his shop. He purchased two kinds of cloth materials: Shirt material that costs 40 per metre and skirt material that cost for & 80 per metre. For every 3 metres of the sk irt material, he bought 4 metres of shirt material. He sold the materials at 12% and 10% profit repectively. If we consider that common ratio as x, then answer the following questions.
69. Find the sale price of skirt material.
(A) 258.8x
(B) 268.8x
(C) 270x
(D) 287.7x
70. Find the sale price of shirt material.
(A) 173x
(B) 174x
(C) 175x
(D) 176x
71.Find the total sale.
(A) 434.8x
(B) 440x
(C) 444.8X
(D) None of these
72.1 total sale is Rs/- 44480, then x =
(A) 100
(B) 200
(C) 300
(D) 400
73. How much shirt material did Rishabh buy, total sale is Rs 44480/-.
(A) 300 metres
(B) 400 metres
(C) 500 metres
(D) 600 metres
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