Question
The Montanez family is a family of 4 people. They have used 3,485.78 gallons of water so far this month. They cannot exceed 7,250.50 gallons per month during drought season. Write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month.
a 4x + 3,485.78 ≤ 7,250.50
b 4x − 3,485.78 ≤ 7,250.50
c 4x − 3,485.78 ≥ 7,250.50
d 4x + 3,485.78 ≥ 7,250.50
a 4x + 3,485.78 ≤ 7,250.50
b 4x − 3,485.78 ≤ 7,250.50
c 4x − 3,485.78 ≥ 7,250.50
d 4x + 3,485.78 ≥ 7,250.50
Answers
GPT-4o
To determine how much water just one member of the Montanez family can use for the remainder of the month, we need to set up an inequality that accounts for the family's total water usage so far and ensures they do not exceed their monthly limit.
Total water usage limit per month = 7,250.50 gallons
Water used so far this month = 3,485.78 gallons
Remaining water = 7,250.50 - 3,485.78 gallons
To find how much water each family member can use for the remainder of the month, we'll let \( x \) represent the amount of water each member can use. Since there are 4 people, the total water usage for the remainder of the month would be \( 4x \).
So, the inequality that represents this situation is:
\[ 4x + 3,485.78 \leq 7,250.50 \]
Option a is correct.
Therefore, the correct inequality is:
\[ \boxed{4x + 3,485.78 \leq 7,250.50} \]
Total water usage limit per month = 7,250.50 gallons
Water used so far this month = 3,485.78 gallons
Remaining water = 7,250.50 - 3,485.78 gallons
To find how much water each family member can use for the remainder of the month, we'll let \( x \) represent the amount of water each member can use. Since there are 4 people, the total water usage for the remainder of the month would be \( 4x \).
So, the inequality that represents this situation is:
\[ 4x + 3,485.78 \leq 7,250.50 \]
Option a is correct.
Therefore, the correct inequality is:
\[ \boxed{4x + 3,485.78 \leq 7,250.50} \]