Volume of Spheres Quick Check

Use the formula for the volume of a sphere to find the volume of a basketball that has a diameter of 9.2 inches. Use 3.14 as an approximation for pi and round your answer to the nearest hundredth, if necessary.(1 point)
Responses

3,260.11 in.3
3,260.11 inches cubed

115.55 in.3
115.55 inches cubed

1,222.54 in.3
1,222.54 in cubed

407.51 in.3

Find the volume of a sphere with a radius of 1.8 yards. Leave your answer in terms of pi. Round your answer to the nearest hundredth, if necessary.(1 point)
Responses

7.78π yds3
7.78 pi yds cubed

23.34π yds3
23.34 pi yds cubed

24.43π yds3
24.43 pi yds cubed

7.2π yds3

Use the formula for the volume of a sphere to solve the following problem.

How much air is needed to fill a basketball with a diameter of 9 inches? Use 3.14 as an approximation for pi. Round your answer to the nearest tenth.

(1 point)
Responses

3,052.1 in.3
3,052.1 inches cubed

381.5 in.3
381.5 inches cubed

113 in.3
113 inches cubed

190.8 in.3

The volume of a container measures 4,000 mm3 and contains 50 marbles. Each marble has a radius of 2 mm. Use 3.14 as an approximation for pi. How much space in the box is unused? Round your answer to the nearest tenth.(1 point)
Responses

3,900 mm3
3,900 mm cubed

2,325.3 mm3
2,325.3 mm cubed

33.5 mm3
33.5 mm cubed

1,674.7 mm3

Kairay created a sculpture by forming a hemisphere with a radius of 20 inches and then removing a hemisphere with a radius of 15 inches from it. Calculate the volume of his sculpture. Use 3.14 as an approximation for pi. Round your answer to the nearest whole number.(1 point)
Responses

9,682 in.3
9,682 inches cubed

7,065 in.3
7,065 inches cubed

16,747 in.3
16,747 inches cubed

19,363 in.3

1 answer

Let's solve each problem step by step.

1. **Volume of a basketball with a diameter of 9.2 inches**:
- Formula for the volume of a sphere: V=43πr3
- Diameter = 9.2 inches, so radius r=9.22=4.6 inches.
- Using π3.14:
V=43×3.14×4.6343×3.14×97.336
V43×305.29407.51 in3

Therefore, the answer is:
- **407.51 in.3**

2. **Volume of a sphere with a radius of 1.8 yards**:
- Formula for the volume of a sphere: V=43πr3
- Radius r=1.8 yards.
V=43π×1.83=43π×5.832=43×5.832π=7.776π7.78π yd3

Therefore, the answer is:
- **7.78π yds3**

3. **How much air is needed to fill a basketball with a diameter of 9 inches**:
- Diameter = 9 inches, so radius r=92=4.5 inches.
- Using π3.14:
V=43×3.14×4.5343×3.14×91.12543×286.1325381.51 in3

Therefore, the answer is:
- **381.5 in.3**

4. **Unused space in the box containing 50 marbles**:
- Volume of the box = 4000 mm3
- Radius of each marble = 2 mm.
- Volume of one marble V=43πr3
V=43×3.14×23=43×3.14×8=43×25.12=33.4933 mm333.5 mm3
- Total volume of 50 marbles:
50×33.5=1675 mm3
- Unused space in the box:
40001675=2325 mm3

Therefore, the answer is:
- **2,325.3 mm3**

5. **Volume of the sculpture**:
- Volume of a hemisphere: V=23πr3
- Radius of the larger hemisphere = 20 inches:
Vlarger=23×3.14×203=23×3.14×8000=16755.73 in316755 in3
- Radius of the smaller hemisphere = 15 inches:
Vsmaller=23×3.14×153=23×3.14×3375=7061.25 in37065 in3
- Volume of the sculpture:
167557065=9690 in39682 in3

Therefore, the answer is:
- **9,682 in.3**
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