On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3) crosses the x-axis at (negative 4, 0) and crosses the y-axis at (0, negative 3).

To determine which statement is true about the graphed function, we need to analyze where the function is positive or negative. Key points given are:

- The function has a minimum value at \(( -2.5, -12 )\).
- The function has a maximum value at \(( 0, -3 )\).
- It crosses the x-axis at \(( -4, 0 )\).
- It crosses the y-axis at \(( 0, -3 )\).

We can infer the behavior of the function around these points:

1. **Between \( -\infty \) and -4**:
Before the function reaches \( x = -4 \), it crosses the x-axis at \( (-4, 0) \). Since it is at 0 at \( x = -4 \) and goes to some negative value below this point because it has a minimum at \( x = -2.5 \), the function must be negative in this region.

2. **Between -4 and -2.5**:
Since \( x = -2.5 \) is the minimum and the function is continuous, it stays negative between \( x = -4 \) and \( x = -2.5 \).

3. **Between -2.5 and 0**:
The function gradually increases from its minimum at \( (-2.5, -12) \) to the maximum at \( (0, -3) \). Since \( (0, -3) \) is still below the x-axis, the function is negative in this interval as well.

4. **Right of \( x = 0 \)**:
Since \( x = 0 \) corresponds to \( y = -3 \), and this is the maximum value, the graph could not indicate any portion to the right of this point crossing the x-axis, so we don't need to consider this interval for this problem.

Based on this information, we can see:

- \( F(x) \) is negative for intervals \( (-\infty, -4) \), \( (-4, -2.5) \), and \( (-2.5, 0) \).
- None of these intervals include positive values for \( F(x) \).

The relevant statement matching these observations is:

**F(x) < 0 over the interval (-∞, -4)**