Question
What is the inverse of the function f(x) = 2x – 10?
h(x) = 2x – 5
h(x) = 2x + 5
h(x) = one-halfx – 5
h(x) = one-halfx + 5
h(x) = 2x – 5
h(x) = 2x + 5
h(x) = one-halfx – 5
h(x) = one-halfx + 5
Answers
Answered by
GPT-4o
To find the inverse of the function \( f(x) = 2x - 10 \), we need to follow a few steps:
1. Replace \( f(x) \) with \( y \):
\[
y = 2x - 10
\]
2. Switch \( x \) and \( y \):
\[
x = 2y - 10
\]
3. Solve for \( y \) to get the inverse function. First, isolate \( y \):
\[
x + 10 = 2y
\]
\[
y = \frac{x + 10}{2}
\]
4. Rewrite \( y \) as \( f^{-1}(x) \):
\[
f^{-1}(x) = \frac{x + 10}{2}
\]
This can also be written as:
\[
f^{-1}(x) = \frac{1}{2}x + 5
\]
Therefore, the inverse function is:
\[
h(x) = \frac{1}{2}x + 5
\]
So, the correct option is:
\[
h(x) = \frac{1}{2}x + 5
\]
In the provided choices, it would correspond to:
h(x) = one-halfx + 5
1. Replace \( f(x) \) with \( y \):
\[
y = 2x - 10
\]
2. Switch \( x \) and \( y \):
\[
x = 2y - 10
\]
3. Solve for \( y \) to get the inverse function. First, isolate \( y \):
\[
x + 10 = 2y
\]
\[
y = \frac{x + 10}{2}
\]
4. Rewrite \( y \) as \( f^{-1}(x) \):
\[
f^{-1}(x) = \frac{x + 10}{2}
\]
This can also be written as:
\[
f^{-1}(x) = \frac{1}{2}x + 5
\]
Therefore, the inverse function is:
\[
h(x) = \frac{1}{2}x + 5
\]
So, the correct option is:
\[
h(x) = \frac{1}{2}x + 5
\]
In the provided choices, it would correspond to:
h(x) = one-halfx + 5
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