14. If the volume of a sphere is 268.08 cm cubed.

What is the surface area of the sphere?
201.06 cm squared
314.16 cm squared
452.39 cm squared
804.25 cm squared

1 answer

To solve this problem, we need to use the formulas for the volume and surface area of a sphere.

The volume \( V \) of a sphere is given by:
\[ V = \frac{4}{3} \pi r^3 \]

Given the volume \( V \) is 268.08 cm³, we can solve for the radius \( r \):

\[ 268.08 = \frac{4}{3} \pi r^3 \]

First, solve for \( r^3 \):

\[ r^3 = \frac{268.08 \times 3}{4 \pi} \]

\[ r^3 = \frac{804.24}{4 \pi} \]

Using \( \pi \approx 3.1416 \):

\[ r^3 = \frac{804.24}{12.5664} \]

\[ r^3 = 64 \]

Next, solve for \( r \) by taking the cube root of both sides:

\[ r = \sqrt[3]{64} \]

\[ r = 4 \, \text{cm} \]

The surface area \( A \) of a sphere is given by:

\[ A = 4 \pi r^2 \]

Using \( r = 4 \) cm:

\[ A = 4 \pi (4)^2 \]

\[ A = 4 \pi \times 16 \]

\[ A = 64 \pi \]

Using \( \pi \approx 3.1416 \):

\[ A \approx 64 \times 3.1416 \]

\[ A \approx 201.06 \, \text{cm}^2 \]

So, the surface area of the sphere is \(\boxed{201.06 \, \text{cm}^2}\).