To find the acceleration of the car, we can use the following kinematic equation:
\[ a = \frac{\Delta v}{\Delta t} \]
where:
- \( \Delta v \) is the change in velocity
- \( \Delta t \) is the change in time
Given:
- Initial velocity (\(v_i\)) = 35.2 m/s
- Final velocity (\(v_f\)) = 45.0 m/s
- Time interval (\(\Delta t\)) = 2.25 s
First, we calculate the change in velocity (\(\Delta v\)):
\[ \Delta v = v_f - v_i \]
\[ \Delta v = 45.0 \, \text{m/s} - 35.2 \, \text{m/s} \]
\[ \Delta v = 9.8 \, \text{m/s} \]
Next, we use the kinematic equation to find the acceleration (\(a\)):
\[ a = \frac{\Delta v}{\Delta t} \]
\[ a = \frac{9.8 \, \text{m/s}}{2.25 \, \text{s}} \]
\[ a \approx 4.36 \, \text{m/s}^2 \]
So, the acceleration of the car is approximately \(4.36 \, \text{m/s}^2\).
a car moving at 35.2 m/s acceleratates uniformly to 45.0 m/s over 2.25s. what is the acceleration of the car?
a=[?]m/s^2
1 answer