To determine the acceleration of the car, we can use the formula for uniform acceleration:
\[ a = \frac{\Delta v}{\Delta t} \]
where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the change in time.
Given:
- The initial velocity (\( v_0 \)) is 0 m/s (since the car is initially at rest),
- The final velocity (\( v \)) is 15.0 m/s,
- The time interval (\( \Delta t \)) is 6.00 seconds.
First, calculate the change in velocity (\( \Delta v \)):
\[ \Delta v = v - v_0 = 15.0 \, \text{m/s} - 0 \, \text{m/s} = 15.0 \, \text{m/s} \]
Now, plug the values into the formula:
\[ a = \frac{15.0 \, \text{m/s}}{6.00 \, \text{s}} = 2.50 \, \text{m/s}^2 \]
So, the acceleration of the car is \( 2.50 \, \text{m/s}^2 \).
a car initially at rest, accelerates uniformly to 15.0 m/s over 6.00s. What is the acceleration of the car?
a=[?] m/s^2
1 answer