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Suppose you have 52 feet of fencing to enclose a rectangular dog pen. The function A=26-x^2 , where x = width, gives you the ar...Asked by fish
17.
Suppose you have 52 feet of fencing to enclose a rectangular dog pen. The function , where x = width, gives you the area of the dog pen in square feet. What width gives you the maximum area? What is the maximum area? Round to the nearest tenth as necessary.
width = 13 ft; area = 507 ft2
width = 13 ft; area = 169 ft2
width = 26 ft; area = 169 ft2
width = 26 ft; area = 364 ft2
Suppose you have 52 feet of fencing to enclose a rectangular dog pen. The function , where x = width, gives you the area of the dog pen in square feet. What width gives you the maximum area? What is the maximum area? Round to the nearest tenth as necessary.
width = 13 ft; area = 507 ft2
width = 13 ft; area = 169 ft2
width = 26 ft; area = 169 ft2
width = 26 ft; area = 364 ft2
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