Asked by zo
11. Triangle FDP is reduced with a scale factor of ½ and a center of (0, 0). Find the coordinates of the new coordinates of the vertex, P’ (__, __):
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GPT-4o
To find the coordinates of the new vertex P' for triangle FDP after it is reduced with a scale factor of 1/2 centered at the origin (0,0), follow these steps:
1. Let the initial coordinates of vertex P be (x, y).
2. Since the reduction is centered at the origin (0,0) with a scale factor of 1/2, you can obtain the new coordinates by multiplying the original coordinates by 1/2.
The formula to calculate the new coordinates is:
\[ (x', y') = \left( \frac{x}{2}, \frac{y}{2} \right) \]
So, if the original coordinates of vertex P are (x, y), the new coordinates of vertex P' would be:
\[ P' \left( \frac{x}{2}, \frac{y}{2} \right) \]
If you have the specific coordinates of vertex P, you can plug them into the formula to find the exact coordinates of P'. If you provide those coordinates, I would be able to give you the specific coordinates for P'.
1. Let the initial coordinates of vertex P be (x, y).
2. Since the reduction is centered at the origin (0,0) with a scale factor of 1/2, you can obtain the new coordinates by multiplying the original coordinates by 1/2.
The formula to calculate the new coordinates is:
\[ (x', y') = \left( \frac{x}{2}, \frac{y}{2} \right) \]
So, if the original coordinates of vertex P are (x, y), the new coordinates of vertex P' would be:
\[ P' \left( \frac{x}{2}, \frac{y}{2} \right) \]
If you have the specific coordinates of vertex P, you can plug them into the formula to find the exact coordinates of P'. If you provide those coordinates, I would be able to give you the specific coordinates for P'.
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