To determine the equation of a line in slope-intercept form (which is \( y = mx + b \)), you need two things: the slope \( m \) and the y-intercept \( b \).
Given:
- The line passes through the point \( (2, -5) \).
However, just this one point is provided, which is insufficient to find a unique line unless we assume a default slope or other information. If we assume you're looking for the general form passing through this point, we'll establish an unknown slope.
1. General form for any line passing through \( (2, -5) \):
\[ y + 5 = m(x - 2) \]
2. Rearrange into slope-intercept form \( y = mx + b \):
\[ y + 5 = mx - 2m \]
\[ y = mx - 2m - 5 \]
So, the general equation of the line passing through the point \( (2, -5) \) in slope-intercept form is:
\[ y = mx - 2m - 5 \]
If you have a specific slope \( m \) in mind, you can substitute it into this equation to get a specific line equation. Can you please provide the slope or any other points this line passes through?
what’s the equation of the line that passes through the points 2 and -5 in slope intercept form
1 answer