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Function for y=-2/5x+3
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GPT-4o
Sure! The equation \( y = -\frac{2}{5}x + 3 \) is a linear equation in slope-intercept form, where \( y \) is the dependent variable and \( x \) is the independent variable. The slope-intercept form is generally written as:
\[ y = mx + c \]
Here, \( m \) represents the slope of the line and \( c \) represents the y-intercept. For the equation \( y = -\frac{2}{5}x + 3 \):
- The slope (\( m \)) is \( -\frac{2}{5} \), which indicates that for every 5 units increase in \( x \), \( y \) decreases by 2 units.
- The y-intercept (\( c \)) is 3, which means the line crosses the y-axis at \( y = 3 \).
To create a function in programming (e.g. Python) that evaluates this equation given an \( x \) value, you can define it as follows:
```python
def linear_function(x):
return (-2/5) * x + 3
# Example usage:
x_value = 10
y_value = linear_function(x_value)
print(f"When x = {x_value}, y = {y_value}")
```
This code defines a function named `linear_function` that takes an `x` value as input and returns the corresponding `y` value based on the linear equation \( y = -\frac{2}{5}x + 3 \).
If you need further help with any other aspect, feel free to ask!
\[ y = mx + c \]
Here, \( m \) represents the slope of the line and \( c \) represents the y-intercept. For the equation \( y = -\frac{2}{5}x + 3 \):
- The slope (\( m \)) is \( -\frac{2}{5} \), which indicates that for every 5 units increase in \( x \), \( y \) decreases by 2 units.
- The y-intercept (\( c \)) is 3, which means the line crosses the y-axis at \( y = 3 \).
To create a function in programming (e.g. Python) that evaluates this equation given an \( x \) value, you can define it as follows:
```python
def linear_function(x):
return (-2/5) * x + 3
# Example usage:
x_value = 10
y_value = linear_function(x_value)
print(f"When x = {x_value}, y = {y_value}")
```
This code defines a function named `linear_function` that takes an `x` value as input and returns the corresponding `y` value based on the linear equation \( y = -\frac{2}{5}x + 3 \).
If you need further help with any other aspect, feel free to ask!
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