To rewrite the equation \( 6q = 3s - 9 \) in function notation, where \( q \) is the independent variable, we need to solve for \( s \) in terms of \( q \).
Starting with the equation:
\[ 6q = 3s - 9 \]
First, isolate \( 3s \):
\[ 3s = 6q + 9 \]
Next, solve for \( s \):
\[ s = \frac{6q + 9}{3} \]
\[ s = 2q + 3 \]
So, the function in terms of \( q \) is:
\[ f(q) = 2q + 3 \]
Therefore, the correct answer is:
\[ f(q) = 2q + 3 \]
Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independent variable.
f of q = one-half q minus three-halves
f(q) = 2s + 3
f of s = one-half s minus three-halves
f(q) = 2q + 3
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