To find the slope (rate of change) of a line that passes through two points, \((x_1, y_1)\) and \((x_2, y_2)\), we use the slope formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Given the points \((-2, -3)\) and \((1, 1)\):
1. Let \((x_1, y_1) = (-2, -3)\)
2. Let \((x_2, y_2) = (1, 1)\)
Substitute these values into the formula:
\[
m = \frac{1 - (-3)}{1 - (-2)}
\]
Simplify the numerator and the denominator:
\[
m = \frac{1 + 3}{1 + 2}
\]
\[
m = \frac{4}{3}
\]
So, the slope of the line that passes through \((-2, -3)\) and \((1, 1)\) is:
\[
m = \frac{4}{3}
\]
Find the slope (rate of change) of a line that passes through (-2,-3) and (1,1).
3 answers
what is with all the typesetting nonsense you have started using?
Just type 4/3 instead of the very obscure and hard-to-read
\[
m = \frac{4}{3}
\]
Just type 4/3 instead of the very obscure and hard-to-read
\[
m = \frac{4}{3}
\]
Apologies for the confusion. To find the slope of the line that passes through the points (-2, -3) and (1, 1):
Use the slope formula:
\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \]
Given points are (-2, -3) as \((x_1, y_1)\) and (1, 1) as \((x_2, y_2)\):
\[ \text{slope} = \frac{1 - (-3)}{1 - (-2)} \]
\[ \text{slope} = \frac{1 + 3}{1 + 2} \]
\[ \text{slope} = \frac{4}{3} \]
So, the slope is 4/3.
Use the slope formula:
\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \]
Given points are (-2, -3) as \((x_1, y_1)\) and (1, 1) as \((x_2, y_2)\):
\[ \text{slope} = \frac{1 - (-3)}{1 - (-2)} \]
\[ \text{slope} = \frac{1 + 3}{1 + 2} \]
\[ \text{slope} = \frac{4}{3} \]
So, the slope is 4/3.