To determine the area of one side of the shoebox that would be identified on its net, let's analyze the dimensions and the possible areas of the faces. The shoebox has dimensions of 72.5 cm, 47.5 cm, and 104 cm. The net of the shoebox would include the following rectangular faces:
1. Two faces measuring 72.5 cm × 47.5 cm
2. Two faces measuring 72.5 cm × 104 cm
3. Two faces measuring 47.5 cm × 104 cm
Let's calculate the area of each of these faces separately:
1. Area of one face measuring 72.5 cm × 47.5 cm:
\[
72.5 \times 47.5 = 3443.75 \, \text{cm}^2
\]
2. Area of one face measuring 72.5 cm × 104 cm:
\[
72.5 \times 104 = 7540 \, \text{cm}^2
\]
3. Area of one face measuring 47.5 cm × 104 cm:
\[
47.5 \times 104 = 4940 \, \text{cm}^2
\]
Among the options provided:
- 31,847.5 cm²
- 358,150 cm²
- 224 cm²
- 7,540 cm²
The correct option that matches one of our calculated areas is 7,540 cm², which corresponds to one of the faces measuring 72.5 cm × 104 cm.
Thus, one area that would be identified on the box’s net is 7,540 cm².
Jeni is painting a flattened shoebox for a school project. The shoebox measures 72.5 cm x 47.5 cm x 104 cm. What is one area that would be identified on the box’s net?(1 point)
Responses
31,847.5 cm2
31,847.5 cm squared
358,150 cm2
358,150 cm squared
224 cm2
224 cm squared
7,540 cm2
1 answer