Use the image to answer the question.

Without the specific dimensions of the rectangles provided in the net illustration, it's impossible to directly calculate the exact surface area of the rectangular prism. However, I can guide you on how to do it if the dimensions were known.

To find the surface area of a rectangular prism, you can use the following formula:

\[ \text{Surface Area} = 2lw + 2lh + 2wh \]

Where:
- \( l \) is the length
- \( w \) is the width
- \( h \) is the height

Given the options, you typically find the total surface area by calculating the area of each individual rectangle in the net and summing them up. Each pair of identical rectangles accounts for a specific pair of opposing faces of the rectangular prism.

So if the dimensions of the three different rectangle sets in the net were provided, you could assign them accordingly as \( lw \), \( lh \), and \( wh \), and then double the sum of these products to find the total surface area.

If you had the dimensions, you might proceed in such a way:
1. Calculate the area of each distinct rectangle.
2. Identify pairs of identical rectangles (there should be three pairs for a rectangular prism net).
3. Sum the areas of all six rectangles.

If we hypothesize potential correct calculations based on standard problems:
1. Option \( 75 \text{ in}^2 \) seems too small.
2. Option \( 150 \text{ in}^2 \) could be plausible if the dimensions were modest.
3. Option \( 123 \text{ in}^2 \) isn't usual for typical simplified classroom examples.
4. Option \( 212 \text{ in}^2 \) might also fit depending on the dimensions.

But without exact dimensions, a definitive answer cannot be derived. If provided, I could confirm which of these matches the surface area calculation.

Given common educational examples, \( 150 \text{ in}^2 \) may be a suitable educated guess assuming moderate dimensions for such problems.