Apply the Zero Power Rule to create an equivalent expression to 9⋅(−33)0+32(8−270) .(2 points)

Question

9⋅(−33)0+32(8−270) =
⋅
+32(
–
)

Answer 1

To apply the Zero Power Rule, we need to remember that any nonzero number raised to the power of zero is equal to 1.

Given the expression:
\[ 9 \cdot (-33)^0 + 32(8 - 270) \]

First, simplify \((-33)^0\):
\[ (-33)^0 = 1 \]

So the expression becomes:
\[ 9 \cdot 1 + 32(8 - 270) \]

Next, simplify the expression inside the parentheses (8 - 270):
\[ 8 - 270 = -262 \]

Therefore, the expression becomes:
\[ 9 \cdot 1 + 32(-262) \]

Now, put everything together:
\[ 9 \cdot 1 + 32(-262) \]
\[ 9 + 32(-262) \]

To match the requested format:
\[ 9 \cdot 1 + 32(8 - 270) = \]
\[ 9 \cdot 1 + 32(-262) \]

Final equivalent expression:
\[ 9 \cdot 1 + 32(-262) \]

So:
\[ 9 \cdot 1 + 32(-262) \]