To convert the inequality \(-6x + 3y \geq -45\) to slope-intercept form (\(y \geq mx + b\) or \(y \leq mx + b\)), follow these steps:
1. Isolate the term with \(y\) on one side of the inequality:
\[
-6x + 3y \geq -45
\]
Add \(6x\) to both sides:
\[
3y \geq 6x - 45
\]
2. Divide every term by 3 to solve for \(y\):
\[
\frac{3y}{3} \geq \frac{6x}{3} - \frac{45}{3}
\]
Simplifying each term, you get:
\[
y \geq 2x - 15
\]
So, the inequality in slope-intercept form is:
\[ y \geq 2x - 15 \]
This matches the option:
\[ y \geq 2x - 15 \]
6.
Write the following inequality in slope-intercept form.
−6x + 3y ≥ −45
y ≤ 2x − 15
y ≥ 2x + 15
y ≥ 2x − 15
y ≤ 2x + 15
1 answer