The volumes of two similar solids are 857.5 mm^3 and 540 mm^3. The surface area of the smaller solid is 108 mm^2. What is the surface area of the larger solid? (1 point)

Let the surface area of the larger solid be x.

Since the two solids are similar, the ratio of their volumes is equal to the cube of the ratio of their corresponding dimensions.

Let the dimensions of the smaller solid be a and the larger solid be b.

Volume ratio => (Volume of larger solid)/(Volume of smaller solid) = (b^3) / (a^3) = 857.5 / 540

Given, the volumes are 857.5 mm^3 and 540 mm^3

=> b^3 / a^3 = 857.5 / 540
=> b^3 / a^3 = 857.5 / 540
=> b / a = cube root(857.5/540) = cube root(1.588)

Therefore, the ratio of the dimensions between the two similar solids is approximately 1.106.

Therefore, the surface area of the larger solid will be the square of the ratio multiplied by the surface area of the smaller solid.

x = 1.106^2 * 108
x = 1.229 * 108
x ≈ 132.75 mm^2

Therefore, the surface area of the larger solid is approximately 132.75 mm^2.