two charges Q1 and Q2 are separated by an unknown distance. they exert a force of 7.6 N on each other. Q1 is 4.4uC and Q2 is 5.5uC. how far apart are the charges in meters?

Answer 1

To find the distance between the charges, we can use Coulomb's law:

F = k * |Q1 * Q2| / r^2

where:
F = force between the charges = 7.6 N
k = Coulomb's constant = 9 x 10^9 N m^2/C^2
Q1 = 4.4 uC = 4.4 x 10^-6 C
Q2 = 5.5 uC = 5.5 x 10^-6 C
r = distance between the charges (unknown)

Now, substitute the given values into the equation:

7.6 = (9 x 10^9) * |4.4 x 10^-6 * 5.5 x 10^-6| / r^2

7.6 = (9 x 10^9) * |2.42 x 10^-11| / r^2

7.6 = (2.178 x 10^-1) / r^2

r^2 = (2.178 x 10^-1) / 7.6

r^2 = 2.864 x 10^-2

r = √(2.864 x 10^-2)

r = 0.169 meters

Therefore, the charges are approximately 0.169 meters apart.