I wonder if you know the implications of this problem? A solution that is 2.07 m in the solute in which the SOLVENT is 6450 g is easy enough to do. But if you want the total solution (solvent + solute) to weigh 6.45 kg, that's another ball game.
m = moles/kg solvent
2.07 = moles/6.45
moles = 2.07 x 6.45 = 13.35 moles, then
moles x molar mass C4H8O = grams of the solute needed. You can go through the densities to calculate the volume. But this gives a mass of the solvent equal to 6.45 kg and not a total mass of 6.45 kg.
Calculate the mass ( kg ) of the solute C4H8O and the volume ( mL ) of the solvent C6H6 that should be combined to generate 6450 g of a solution that is 2.07 m C4H8O.
Density (kg/l)
C4H8O 0.8892
C6H6 0.8786
1 answer