Asked by sh
What is the Keq of Cl2(aq) + 2HI2(g) -> I2(s) + 2HCl(s)
Solid is not included in the Keq expression, so what would Keq be?
Thanks in advance.
Solid is not included in the Keq expression, so what would Keq be?
Thanks in advance.
Answers
Answered by
DrBob222
I wonder if HCl is a solid or (aq). I don't know what HI2 is; I suspect that is a typo and should be 2HI. That equation isn't balanced as is. If as shown, then
Kc = 1/(Cl2)(HI)^2
Kc = 1/(Cl2)(HI)^2
Answered by
sh
There are 3 mols on each side. I made the question up, so I think HCl was supposed to be a gas.
I was just wondering if it would be Keq = 0/(Cl2)(HI)^2 or Keq= 1/(Cl2)(HI)^2. Thanks for clearing it up.
I was just wondering if it would be Keq = 0/(Cl2)(HI)^2 or Keq= 1/(Cl2)(HI)^2. Thanks for clearing it up.
Answered by
DrBob222
No, Keq can't be zero on top. By definition, the activity of a solid is 1; therefore, 1 goes on top.
For the balancing, you do not balance total moles to equal total moles. You DO balance moles (or atoms) of individual elements. So a balanced equation could be
Cl2(aq) + 2HI(g) ==>I2(s) + 2HCl(s)
For the balancing, you do not balance total moles to equal total moles. You DO balance moles (or atoms) of individual elements. So a balanced equation could be
Cl2(aq) + 2HI(g) ==>I2(s) + 2HCl(s)
Answered by
sh
Whoops, forgot the rules to balancing an equation for a second, thanks! :)
Is the activity of pure liquids, 1, as well?
Is the activity of pure liquids, 1, as well?
Answered by
DrBob222
Yes, the activity of a pure liquid is 1. The activity of a pure solid is 1.
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