What is the product of sqrt6 ​ and 9sqrt12 ​ in simplest radical form?

Answer 1

To find the product of √6 and 9√12, we simply multiply the numbers outside the square roots and then multiply the numbers inside the square roots.

(√6) * (9√12) = 9√6 * √12 = 9 * √(6 * 12) = 9 * √72.

Now, we simplify the radical:

√72 = √(36 * 2) = √36 * √2 = 6√2.

Therefore, the product of √6 and 9√12 in simplest radical form is 54√2.