If a force of 50N stretches a wire from 20m to 20.01m,what is the amount of force required to stretch the same material from 20m to 20.05m

Answer 1

To find the amount of force required to stretch the wire from 20m to 20.05m, we can use Hooke's Law which states that the force required to stretch or compress a spring is directly proportional to the displacement.

First, let's calculate the spring constant (k) using the initial force and displacement.
F = kx
50N = k(20.01m - 20m)
50N = k(0.01m)
k = 50N / 0.01m
k = 5000 N/m

Now, we can calculate the force required to stretch the wire from 20m to 20.05m using the same spring constant.
F = kx
F = 5000 N/m * (20.05m - 20m)
F = 5000 N/m * 0.05m
F = 250 N

Therefore, the amount of force required to stretch the wire from 20m to 20.05m is 250N.